Re: Lost d20, how do you use 3d6 system to replace it lol?
No doubt this won't hold up to mathematical scrutiny or elegance, but my first thought would be to roll 3d6, then on a result of '3' or '18' roll another d6.
If you rolled a '3' first, or "Low," the subsequent d6 would be 1-2 = 1, 3-4 = 2, 5-6 = 3 (really '3' this time).
Then if you roll a natural '18', or "High," the subsequent d6 would be 1-2 = 18, 3-4 = 19, 5-6 = 20.